Statistics is the science of learning from data. Real questions โ Is this town getting warmer? Do students who revise longer score higher? โ are answered by collecting data, summarising it, and interpreting what it shows, while being honest about what it does not show.
Variance and standard deviation · interpolation for grouped data
Formal outlier rules · cleaning data · a large data set
| Word | Meaning | Example |
|---|---|---|
| Population | Everything or everyone of interest. | All adults in a town |
| Sample | A subset of the population. | $100$ of those adults |
| Sampling frame | The list the sample is chosen from. | The electoral register |
| Qualitative | Non-numerical data. | Favourite sport |
| Discrete | Numerical; only particular values. | Number of pets |
| Continuous | Numerical; any value in a range. | Time, mass |
| Bivariate | Two variables measured on each item. | Height and arm span |
| Outlier | A value far from the rest of the data. | A $95$ among values $20$โ$64$ |
| Bias | A systematic distortion in a sample or result. | Surveying only gym users about exercise |
For $16$ values, $\sum x = 192$ and $\sum x^2 = 2560$. The largest value is $22$. (a) Find the mean and standard deviation. (b) Is $22$ an outlier using $\bar{x} \pm 2\sigma$?
Everything in DfE content areas K and L, and the page that covers it.
- KStatistical SamplingPopulations, samples and sampling frames; random and non-random sampling methods; their advantages, disadvantages and sources of bias.
- LPresenting DataHistograms with frequency density, cumulative frequency, box plots and scatter diagrams; comparing distributions.
- LMeasures of Location and SpreadMean, median, mode, quartiles and percentiles; interpolation; variance and standard deviation; choosing measures.
- LCorrelation and OutliersScatter diagrams and regression lines, correlation and causation, outliers and cleaning data.
Random methods
Simple random, systematic, stratified (need a frame).
Non-random
Quota, opportunity (no frame).
Histogram
Frequency density $=$ frequency $\div$ width.
Grouped median
Interpolate at $\tfrac{n}{2}$.
Variance
Mean of squares $-$ square of mean.
Skewed data
Median and IQR.
Symmetric data
Mean and standard deviation.
Outlier rules
$1.5 \times$ IQR beyond quartiles; or $2\sigma$/$3\sigma$ from mean.
Extrapolation
Outside the data โ unreliable.
Ten questions drawing on the whole Statistics topic. Work each one through before opening the solution.
Classify each variable: (a) number of siblings; (b) time to run $100$ m; (c) eye colour.
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(a) Quantitative, discrete. (b) Quantitative, continuous. (c) Qualitative.
Describe how to take a systematic sample of $50$ from a numbered list of $1000$ customers.
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Interval $k = \dfrac{1000}{50} = 20$. Choose a random start $r$ from $1$ to $20$, then take customers $r, r + 20, r + 40, \ldots$ up to $50$ customers.
A school has $360$ students in Year 12 and $240$ in Year 13. Find the numbers from each year in a stratified sample of $40$.
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Total $600$. Year 12: $\dfrac{360}{600} \times 40 = 24$. Year 13: $\dfrac{240}{600} \times 40 = 16$.
Find the mean, median and mode of $3, 7, 8, 8, 10, 12, 15$.
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$\sum x = 63$, so $\bar{x} = 9$. Median (4th value) $= 8$. Mode $= 8$.
For $10$ values, $\sum x = 120$ and $\sum x^2 = 1650$. Find the mean and standard deviation.
โถ Show solution
$\bar{x} = 12$. $\sigma^2 = 165 - 144 = 21$, so $\sigma = \sqrt{21} = 4.58$ (3 s.f.).
For the data $4, 6, 7, 8, 9, 10, 11, 12, 13, 30$, find the quartiles and decide whether $30$ is an outlier using the $1.5 \times \text{IQR}$ rule.
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Median $= \dfrac{9 + 10}{2} = 9.5$. Lower half $4, 6, 7, 8, 9$ gives $Q_1 = 7$; upper half $10, 11, 12, 13, 30$ gives $Q_3 = 12$.
IQR $= 5$; upper fence $12 + 7.5 = 19.5$. Since $30 > 19.5$, it is an outlier.
In a grouped frequency table, the class $10 \leqslant t < 20$ has frequency $30$ and $20 \leqslant t < 40$ has frequency $24$. Find the frequency densities, and explain why the second bar is shorter even though its frequency is similar.
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$30 \div 10 = 3$ and $24 \div 20 = 1.2$.
The second class is twice as wide, so its values are spread more thinly; area, not height, represents frequency.
For cars aged $1$ to $8$ years, the regression line of value $y$ (ยฃ1000s) on age $x$ (years) is $y = 18.4 - 1.6x$. (a) Interpret $-1.6$. (b) Explain why the line should not be used for a $15$-year-old car.
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(a) For each extra year of age, a car's value falls by about ยฃ$1600$.
(b) $15$ years is outside the data range: extrapolation. Indeed the line gives $18.4 - 24 = -5.6$, a negative value, which is impossible.
Daily maximum temperatures in June: Town A mean $15.2\,^\circ$C, standard deviation $3.1\,^\circ$C; Town B mean $12.8\,^\circ$C, standard deviation $5.4\,^\circ$C. Compare the two towns.
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Town A had the higher mean, so on average it was warmer.
Town A had the smaller standard deviation, so its temperatures were more consistent; Town B's varied more from day to day.
The number of books $x$ read last month by $40$ students is shown.
| $x$ | $0$ | $1$ | $2$ | $3$ | $4$ | $5$ |
|---|---|---|---|---|---|---|
| $f$ | $4$ | $10$ | $12$ | $8$ | $4$ | $2$ |
(a) Find the mean and standard deviation. (b) Find the median and interquartile range. (c) Is $x = 5$ an outlier using (i) $\bar{x} \pm 2\sigma$; (ii) the $1.5 \times \text{IQR}$ rule? (d) The students were the members of a school reading club. Explain why the results should not be used to estimate the number of books read by all students in the school.
โถ Show solution
(a) $\sum fx = 0 + 10 + 24 + 24 + 16 + 10 = 84$, so $\bar{x} = 2.1$.
$\sum fx^2 = 0 + 10 + 48 + 72 + 64 + 50 = 244$, so $\sigma^2 = \dfrac{244}{40} - 2.1^2 = 6.1 - 4.41 = 1.69$ and $\sigma = 1.3$.
(b) Cumulative frequencies: $4, 14, 26, 34, 38, 40$.
Median: $20$th and $21$st values are both $2$, so median $= 2$.
$Q_1$: $10$th and $11$th values are both $1$. $Q_3$: $30$th and $31$st values are both $3$. IQR $= 2$.
(c)(i) $2.1 + 2(1.3) = 4.7$; $5 > 4.7$, so $5$ is an outlier by this rule.
(ii) $Q_3 + 1.5 \times 2 = 6$; $5 < 6$, so $5$ is not an outlier by this rule. Different rules can give different conclusions.
(d) Reading-club members are not representative of all students โ they are likely to read more than average โ so the sample is biased and would overestimate the school's mean.