The Goal: Every whole number greater than 1 is either a prime number itself, or it can be broken down into a specific list of prime numbers multiplied together.
This list is unique—like a numerical fingerprint. Finding this list is called Prime Factorization.
Remember your first few primes: 2, 3, 5, 7, 11, 13, 17...
When you find the prime factors, you must write the final answer using powers (indices). Don't just leave a long list of numbers.
If you find: \(2 \times 2 \times 2 \times 3 \times 5 \times 5\)
Write it as: \(2^3 \times 3 \times 5^2\)
This is the most popular method. You keep splitting numbers into pairs of factors until you only have primes left.
Strategy: Split 120 into any two numbers. Circle primes as you find them. Keep splitting the others.
Collect all the circled primes: \(2, 2, 2, 3, 5\).
This method is tidier for larger numbers. You keep dividing by the smallest prime number possible until you reach 1.
Strategy: Draw a line. Put the number on the right. Divide by small primes (start with 2) and put the result underneath.
We reached 1, so we stop. Collect the primes used: \(2, 2, 3, 3, 7\).
No! With a factor tree, you could start 120 as \(2 \times 60\), or \(10 \times 12\), or \(4 \times 30\). As long as your math is correct, you will always end up with the exact same collection of prime numbers at the end.
Find the prime factorization of the following numbers. Give your answers in index form.
Click on the question bar to reveal the worked solution.
Method: Repeated Division by 2
Since 64 is even, we just keep dividing by 2.
\(64 \div \mathbf{2} = 32\)We have six 2s.
Method: Factor Tree approach
1. Split 150 into \(15 \times 10\).
2. Split 15 into \(\mathbf{3} \times \mathbf{5}\). (Both are prime, circle them).
3. Split 10 into \(\mathbf{2} \times \mathbf{5}\). (Both are prime, circle them).
Collecting the primes: \(2, 3, 5, 5\).
Method: Repeated Division
1. It's even, divide by 2: \(98 \div \mathbf{2} = 49\).
2. 49 isn't divisible by 2, 3, or 5. Try 7. \(49 \div \mathbf{7} = 7\).
3. 7 is prime. \(7 \div \mathbf{7} = 1\).
Collecting primes: \(2, 7, 7\).
Method: Factor Tree approach
This is a bigger number, try splitting off the zero first: \(360 = 36 \times 10\).
Branch 1 (The 10): Split into \(\mathbf{2} \times \mathbf{5}\). (Done).
Branch 2 (The 36): Split into \(6 \times 6\).
Split the first 6 into \(\mathbf{2} \times \mathbf{3}\). (Done).
Split the second 6 into \(\mathbf{2} \times \mathbf{3}\). (Done).
Collect all primes found: \(2, 5, 2, 3, 2, 3\).
Group them: Three 2s, two 3s, one 5.
Method: Recognition / Repeated Division
It ends in 5, so we know 5 is a prime factor.
\(625 \div \mathbf{5} = 125\)We found four 5s.