Standard form is a way of writing very large or very small numbers efficiently. It always looks like this:
$$ A \times 10^n $$Move the decimal point to the left until you have a number between 1 and 10. The number of jumps is your power.
Move the decimal point to the right. The number of jumps is your power, but it will be negative.
Multiply the numbers first, then add the powers using index laws. Check your answer is still in standard form!
Divide the numbers, then subtract the powers.
Try these yourself, then click to reveal the solution.
1. Identify the first non-zero digit (7). The decimal goes after it: \(7.05\)
2. Count how many places the decimal moved from the start to get between the 7 and 0.
It moved 5 places to the right.
3. Since the original number was small (less than 1), the power is negative.
Answer: \(7.05 \times 10^{-5}\)Step 1: Multiply the lead numbers
\(4 \times 5 = 20\)
Step 2: Add the powers
\(10^5 \times 10^3 = 10^8\)
Step 3: Check Standard Form
We have \(20 \times 10^8\).
This is NOT in standard form because 20 is not between 1 and 10.
Step 4: Adjustment
Convert 20 to \(2 \times 10^1\).
So, \((2 \times 10^1) \times 10^8 = 2 \times 10^9\)
Step 1: Divide the numbers
\(2.4 \div 8 = 0.3\)
Step 2: Subtract the powers
\(10^8 \div 10^2 = 10^6\)
Step 3: Adjust to Standard Form
We have \(0.3 \times 10^6\). (0.3 is too small).
Move decimal right to make it 3. Subtract 1 from the power.
The power is negative (-3), so the number is small. We move the decimal 3 places to the left.
Start: \(5.6\)
Jump 1: \(0.56\)
Jump 2: \(0.056\)
Jump 3: \(0.0056\)
Answer: 0.0056Warning: You cannot just add the powers for addition!
Method: Convert to ordinary numbers first
\(3 \times 10^4 = 30,000\)
\(2 \times 10^3 = 2,000\)
Add them: \(30,000 + 2,000 = 32,000\)
Convert back to Standard Form:
Answer: \(3.2 \times 10^4\)