Every probability is a number from $0$ to $1$ inclusive. Nothing can be more certain than certain, and nothing less likely than impossible.
| Probability | Word | Example |
|---|---|---|
| $0$ | Impossible | Rolling a $7$ on an ordinary die |
| Close to $0$ | Very unlikely | Winning the lottery jackpot |
| $0.5$ | Even chance | A fair coin landing heads |
| Close to $1$ | Very likely | Rolling less than $6$ on a die |
| $1$ | Certain | Rolling a number less than $7$ |
Mark these events on a probability scale: (a) a fair die showing an even number; (b) the sun rising tomorrow; (c) picking a red card from a standard deck; (d) rolling two sixes with two dice.
A card is drawn at random from a standard pack of $52$. Find (a) $P(\text{a heart})$, (b) $P(\text{a king})$, (c) $P(\text{a picture card})$.
Sometimes you cannot reason out a probability β a drawing pin, a bent coin or a real-world event. Then you must experiment.
A drawing pin is dropped $200$ times and lands point up $124$ times. Estimate the probability that it lands point up.
So $P(\text{point up}) \approx 0.62$. Note the word "estimate" β a different set of $200$ drops would give a slightly different value.
In a factory, $12$ out of $400$ items sampled were faulty. Estimate how many faulty items there would be in a batch of $5000$.
| Theoretical | Experimental (relative frequency) | |
|---|---|---|
| How it is found | By reasoning | By carrying out trials |
| Needs | Equally likely outcomes | Data from an experiment |
| Exactness | Exact | An estimate |
| Useful for | Fair dice, coins, cards | Biased objects, real-world events |
| Improves with | Nothing β it is fixed | More trials |
A die is rolled $600$ times. A six comes up $148$ times. Is the die likely to be fair?
The die is probably biased towards six.
A coin is tossed $20$ times and lands heads $13$ times. Can you conclude the coin is biased?
No β you cannot conclude bias. The sample is too small. Tossing the coin many more times would give a much better estimate.
A four-colour spinner is spun $500$ times.
| Colour | Red | Blue | Green | Yellow |
|---|---|---|---|---|
| Frequency | $145$ | $118$ | $96$ | $141$ |
(a) Estimate $P(\text{green})$. (b) Estimate $P(\text{red or yellow})$. (c) Comment on whether the spinner is fair.
With $500$ trials this suggests the spinner is probably slightly biased, though the evidence is not overwhelming for blue and yellow.
Check: $145 + 118 + 96 + 141 = 500$ β
The scale
$0$ impossible, $0.5$ even chance, $1$ certain. Never outside this range.
Theoretical
$\dfrac{\text{favourable}}{\text{total}}$ β needs equally likely outcomes.
Relative frequency
$\dfrac{\text{times it happened}}{\text{trials}}$ β from real data.
Also called
Experimental probability, or an estimate of probability.
Detecting bias
Compare experimental with theoretical over many trials.
Small samples
Cannot prove bias β the variation could easily be chance.
Predicting
Relative frequency $\times$ new number of trials.
Writing it
Fraction, decimal or percentage β never a ratio.
Describe each probability in words: (a) $0$, (b) $0.5$, (c) $0.95$, (d) $0.03$.
βΆ Show solution
(a) Impossible (b) An even chance (c) Very likely (d) Very unlikely
Explain why a probability of $1.3$ is impossible.
βΆ Show solution
A probability is the fraction of outcomes that are favourable, so it can never exceed the total.
The maximum is $1$, meaning the event is certain. A value of $1.3$ would mean "more than certain", which has no meaning.
A card is drawn from a standard pack. Find (a) $P(\text{a spade})$, (b) $P(\text{a black ace})$, (c) $P(\text{not a heart})$.
βΆ Show solution
(a) $\dfrac{13}{52} = \dfrac{1}{4}$
(b) Two black aces (spades and clubs): $\dfrac{2}{52} = \dfrac{1}{26}$
(c) $1 - \dfrac{1}{4} = \dfrac{3}{4}$
A bottle top is flipped $250$ times and lands upright $85$ times. Estimate the probability that it lands upright.
βΆ Show solution
Relative frequency $= \dfrac{85}{250} = 0.34$
In a quality check, $9$ out of $300$ light bulbs were faulty. Estimate how many would be faulty in a delivery of $12\,000$ bulbs.
βΆ Show solution
Relative frequency $= \dfrac{9}{300} = 0.03$
Expected faulty $= 0.03 \times 12\,000 = 360$ bulbs
A five-sided spinner is spun $400$ times and lands on section A $130$ times. Compare this with the theoretical probability and comment.
βΆ Show solution
Theoretical (if fair): $P(A) = \dfrac{1}{5} = 0.2$, so expect $0.2 \times 400 = 80$.
Experimental: $\dfrac{130}{400} = 0.325$.
$130$ is much greater than the expected $80$, and $400$ trials is a large sample.
The spinner is probably biased towards section A.
Explain the difference between theoretical probability and relative frequency, giving one situation where each is the appropriate tool.
βΆ Show solution
Theoretical probability is calculated by reasoning about equally likely outcomes, e.g. $P(\text{a } 3) = \tfrac{1}{6}$ on a fair die. It is exact and needs no experiment.
Relative frequency is calculated from the results of trials, e.g. dropping a drawing pin $200$ times. It is only an estimate, but it is the only option when outcomes are not equally likely.
A coin is tossed $10$ times and lands heads $7$ times. Josh says "the coin must be biased". Explain why Josh may be wrong.
βΆ Show solution
Ten trials is a very small sample. Getting $7$ heads out of $10$ happens quite often with a perfectly fair coin, just by chance.
To decide about bias, Josh would need to toss the coin many more times β several hundred β and see whether the relative frequency stays away from $0.5$.
The table shows the results of spinning a three-colour spinner $600$ times.
| Colour | Red | Blue | Green |
|---|---|---|---|
| Frequency | $294$ | $205$ | $?$ |
(a) Find the missing frequency. (b) Estimate $P(\text{green})$. (c) Is the spinner fair?
βΆ Show solution
(a) $600 - 294 - 205 = 101$
(b) $\dfrac{101}{600} = 0.168$ (3 d.p.)
(c) A fair three-colour spinner would give about $200$ of each. The results are $294$, $205$, $101$ β red is far too high and green far too low.
The spinner is biased.
A researcher records the relative frequency of a biased coin landing heads after different numbers of tosses.
| Tosses | $10$ | $50$ | $100$ | $500$ | $2000$ |
|---|---|---|---|---|---|
| Relative frequency | $0.9$ | $0.68$ | $0.71$ | $0.685$ | $0.679$ |
(a) Which value is the best estimate of $P(\text{heads})$, and why? (b) Estimate the number of heads in $3000$ tosses. (c) Estimate $P(\text{tails})$. (d) Explain the pattern in the table.
βΆ Show solution
(a) The value from $2000$ tosses, $0.679$. The larger the number of trials, the more reliable the relative frequency as an estimate of the true probability.
(b) $0.679 \times 3000 = 2037$ heads
(c) $P(\text{tails}) = 1 - 0.679 = 0.321$
(d) The early values jump about a lot ($0.9$ then $0.68$), but as the number of tosses increases the relative frequency settles down towards a value of roughly $0.68$. This is the true probability that the experiment is converging on.