๐Ÿš— Compound Measures

GCSE Maths ยท Ratio, Proportion & Rates of Change (R11)

Ages 15โ€“16 ยท Foundation & Higher

โ† Back to topic overview
1 What is a Compound Measure?

A compound measure combines two different measurements into one rate. You will always spot it because its units contain the word "per" or a slash.

MeasureFormulaUnits
Speed$S = \dfrac{D}{T}$m/s, km/h, mph
Density$\rho = \dfrac{M}{V}$g/cmยณ, kg/mยณ
Pressure$P = \dfrac{F}{A}$N/mยฒ (pascal), N/cmยฒ
Rate of pay$\dfrac{\text{pay}}{\text{hours}}$ยฃ/hour
Unit price$\dfrac{\text{cost}}{\text{amount}}$p/g, ยฃ/litre
Population density$\dfrac{\text{people}}{\text{area}}$people/kmยฒ
Flow rate$\dfrac{\text{volume}}{\text{time}}$litres/min
The unit tells you the formula. If a quantity is measured in "grams per cubic centimetre", then you find it by working out grams $\div$ cubic centimetres. You never need to memorise a formula you can read off the units.
2 Formula Triangles

A formula triangle helps you rearrange. Cover the quantity you want, and the triangle shows you what to do with the other two.

D S T Distance ยท Speed ยท Time M ฯ V Mass ยท Density ยท Volume F P A Force ยท Pressure ยท Area
How to read a triangle. Cover $D$ and you see $S \times T$, so $D = S \times T$.
Cover $S$ and you see $D$ over $T$, so $S = \dfrac{D}{T}$.
Cover $T$ and you see $D$ over $S$, so $T = \dfrac{D}{S}$.
3 Speed, Distance and Time
The number one error: writing $1$ hour $45$ minutes as $1.45$ hours. It is $1.75$ hours, because $45 \div 60 = 0.75$.
Worked Example 1 โ€” Finding speed

A train travels $273$ km in $3$ hours $30$ minutes. Find its average speed in km/h.

โ‘ Time in hours: $30 \div 60 = 0.5$, so $T = 3.5$ h.
โ‘ก$S = \dfrac{D}{T} = \dfrac{273}{3.5}$
โ‘ข$= 78$

Answer: $78$ km/h

Worked Example 2 โ€” Finding time

A cyclist rides $63$ km at an average speed of $18$ km/h. How long does the ride take, in hours and minutes?

โ‘ $T = \dfrac{D}{S} = \dfrac{63}{18} = 3.5$ hours
โ‘ก$0.5$ hours $= 0.5 \times 60 = 30$ minutes

Answer: $3$ hours $30$ minutes

Worked Example 3 โ€” Average speed over two stages

A driver travels $80$ km at $80$ km/h, then $80$ km at $40$ km/h. Find the average speed for the whole journey.

โ‘ Stage 1 time $= 80 \div 80 = 1$ hour
โ‘กStage 2 time $= 80 \div 40 = 2$ hours
โ‘ขTotal distance $= 160$ km; total time $= 3$ hours
โ‘ฃAverage speed $= 160 \div 3 = 53.3$ km/h (1 d.p.)
Not $60$ km/h! You cannot average the two speeds, because more time is spent at the slower speed. Always use total distance $\div$ total time.
4 Density, Mass and Volume
Density
$\text{density} = \dfrac{\text{mass}}{\text{volume}}$   ยท   $M = \rho V$   ยท   $V = \dfrac{M}{\rho}$
Worked Example 4 โ€” Finding mass

A steel bar has volume $250\text{ cm}^3$. Steel has density $7.8\text{ g/cm}^3$. Find the mass of the bar in kilograms.

โ‘ $M = \rho \times V = 7.8 \times 250$
โ‘ก$= 1950$ g
โ‘ข$1950 \div 1000 = 1.95$ kg
Worked Example 5 โ€” Density with a solid shape

A solid cylinder of radius $4$ cm and height $10$ cm has mass $1.6$ kg. Find its density in g/cmยณ, to 2 decimal places.

โ‘ Volume $= \pi r^2 h = \pi \times 4^2 \times 10 = 160\pi = 502.65\text{ cm}^3$
โ‘กMass $= 1.6$ kg $= 1600$ g
โ‘ข$\rho = \dfrac{1600}{502.65} = 3.183\ldots$

Answer: $3.18\text{ g/cm}^3$

5 Pressure, Force and Area
Pressure
$\text{pressure} = \dfrac{\text{force}}{\text{area}}$  ยท  $1\text{ N/m}^2 = 1$ pascal (Pa)
Why a drawing pin works. The same push spread over a tiny area gives an enormous pressure โ€” which is why the point goes into the wood and your thumb is unharmed.
Worked Example 6 โ€” Finding pressure

A box exerts a force of $840$ N on the floor through a base measuring $1.2$ m by $0.5$ m. Find the pressure in N/mยฒ.

โ‘ Area $= 1.2 \times 0.5 = 0.6\text{ m}^2$
โ‘ก$P = \dfrac{F}{A} = \dfrac{840}{0.6} = 1400$

Answer: $1400\text{ N/m}^2$ (1400 Pa)

Worked Example 7 โ€” Finding area

A machine must not exert more than $250\text{ N/cm}^2$ on a surface. It presses with a force of $6000$ N. What is the smallest area of contact allowed?

โ‘ $A = \dfrac{F}{P} = \dfrac{6000}{250}$
โ‘ก$= 24\text{ cm}^2$

A smaller area would push the pressure above the limit.

6 Rates of Pay, Unit Pricing and Other Rates
Worked Example 8 โ€” Rate of pay with overtime

Jamal is paid ยฃ$11.60$ per hour for the first $35$ hours each week, and time-and-a-half after that. One week he works $42$ hours. Find his pay.

โ‘ Basic pay $= 35 \times 11.60 = ยฃ406$
โ‘กOvertime hours $= 42 - 35 = 7$
โ‘ขOvertime rate $= 11.60 \times 1.5 = ยฃ17.40$ per hour
โ‘ฃOvertime pay $= 7 \times 17.40 = ยฃ121.80$
โ‘คTotal $= 406 + 121.80 = ยฃ527.80$
Worked Example 9 โ€” Population density

A county has a population of $486\,000$ and an area of $2700\text{ km}^2$. Find its population density.

โ‘ Density $= \dfrac{486\,000}{2700}$
โ‘ก$= 180$

Answer: $180$ people per kmยฒ

Worked Example 10 โ€” Flow rate

Water flows into a tank at $18$ litres per minute. The tank is a cuboid measuring $1.5$ m by $0.8$ m by $0.75$ m. How long does it take to fill, to the nearest minute?

โ‘ Volume $= 1.5 \times 0.8 \times 0.75 = 0.9\text{ m}^3$
โ‘ก$1\text{ m}^3 = 1000$ litres, so volume $= 900$ litres.
โ‘ขTime $= 900 \div 18 = 50$ minutes
7 Quick Reference

Speed

$S = \dfrac{D}{T}$, $D = ST$, $T = \dfrac{D}{S}$.

Density

$\rho = \dfrac{M}{V}$, $M = \rho V$, $V = \dfrac{M}{\rho}$.

Pressure

$P = \dfrac{F}{A}$, $F = PA$, $A = \dfrac{F}{P}$.

Average speed

Total distance $\div$ total time โ€” never average the speeds.

Time as a decimal

Minutes $\div 60$. $1$ h $45$ min $= 1.75$ h.

Units first

Match the units to the rate before calculating.

km/h โ†” m/s

$\div 3.6$ to go to m/s; $\times 3.6$ to come back.

Read the unit

"per" means divide โ€” the unit is the formula.

8 Practice Questions
Question 1

A coach travels $153$ km in $2$ hours $15$ minutes. Find its average speed in km/h.

โ–ถ Show solution

$T = 2 + \dfrac{15}{60} = 2.25$ hours.

$S = \dfrac{153}{2.25} = 68$

Answer: $68$ km/h

Question 2

A runner keeps a steady speed of $4.5$ m/s for $12$ minutes. How far does she run, in kilometres?

โ–ถ Show solution

$12$ minutes $= 12 \times 60 = 720$ seconds.

$D = S \times T = 4.5 \times 720 = 3240$ m

$= 3.24$ km

Question 3

A block of wood has mass $432$ g and volume $540\text{ cm}^3$. Find its density, and say whether it will float in water (density $1\text{ g/cm}^3$).

โ–ถ Show solution

$\rho = \dfrac{432}{540} = 0.8\text{ g/cm}^3$

$0.8 < 1$, so the block is less dense than water and it will float.

Question 4

Gold has a density of $19.3\text{ g/cm}^3$. Find the volume of a gold bar of mass $2$ kg, to 1 decimal place.

โ–ถ Show solution

$2$ kg $= 2000$ g.

$V = \dfrac{M}{\rho} = \dfrac{2000}{19.3} = 103.626\ldots$

Answer: $103.6\text{ cm}^3$

Question 5

A crate weighing $1560$ N stands on a square base of side $0.4$ m. Find the pressure it exerts in N/mยฒ.

โ–ถ Show solution

Area $= 0.4 \times 0.4 = 0.16\text{ m}^2$

$P = \dfrac{1560}{0.16} = 9750$

Answer: $9750\text{ N/m}^2$

Question 6

Convert a speed of $25$ m/s into km/h.

โ–ถ Show solution

$25 \times 3.6 = 90$

Answer: $90$ km/h

Full working: $25$ m/s $= 25 \times 3600 = 90\,000$ m per hour $= 90$ km/h โœ“

Question 7

A driver travels $120$ km at $60$ km/h and then $120$ km at $120$ km/h. Find the average speed for the whole journey.

โ–ถ Show solution

Stage 1 time $= 120 \div 60 = 2$ hours.

Stage 2 time $= 120 \div 120 = 1$ hour.

Total distance $= 240$ km; total time $= 3$ hours.

Average speed $= 240 \div 3 = \mathbf{80}$ km/h.

(Note this is not $90$ km/h โ€” the average of $60$ and $120$.)

Question 8

Sofia is paid ยฃ$13.20$ per hour for a $37$-hour week, plus double time for weekend hours. One week she works $37$ hours plus $6$ hours at the weekend. Find her total pay.

โ–ถ Show solution

Basic $= 37 \times 13.20 = ยฃ488.40$

Weekend rate $= 13.20 \times 2 = ยฃ26.40$ per hour

Weekend pay $= 6 \times 26.40 = ยฃ158.40$

Total $= 488.40 + 158.40 = ยฃ646.80$

Question 9

A swimming pool is $25$ m long, $10$ m wide and has a uniform depth of $1.4$ m. Water flows in at $450$ litres per minute. How long, to the nearest hour, does it take to fill?

โ–ถ Show solution

Volume $= 25 \times 10 \times 1.4 = 350\text{ m}^3$

$350\text{ m}^3 = 350 \times 1000 = 350\,000$ litres

Time $= 350\,000 \div 450 = 777.78$ minutes

$777.78 \div 60 = 12.96$ hours

Answer: about $13$ hours

Question 10

An alloy is made by mixing $300\text{ cm}^3$ of metal A (density $8.9\text{ g/cm}^3$) with $200\text{ cm}^3$ of metal B (density $7.1\text{ g/cm}^3$). Assuming the volumes simply add, find the density of the alloy.

โ–ถ Show solution

Mass of A $= 8.9 \times 300 = 2670$ g

Mass of B $= 7.1 \times 200 = 1420$ g

Total mass $= 2670 + 1420 = 4090$ g

Total volume $= 300 + 200 = 500\text{ cm}^3$

Density $= \dfrac{4090}{500} = \mathbf{8.18\text{ g/cm}^3}$

Sense check: the answer lies between $7.1$ and $8.9$, and closer to $8.9$ because there is more of metal A โœ“

Compound Measures (R11) ยท GCSE Maths Revision ยท Created with MathJax